((x^2-9)/2x)*(6/(3x+9))

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Solution for ((x^2-9)/2x)*(6/(3x+9)) equation: 


D( x )

3*x+9 = 0

3*x+9 = 0

3*x+9 = 0

3*x+9 = 0 // - 9

3*x = -9 // : 3

x = -9/3

x = -3

x in (-oo:-3) U (-3:+oo)

x*((x^2-9)/2)*(6/(3*x+9)) = 0

(6*x*(x^2-9))/(2*(3*x+9)) = 0

( x )

x = 0

( x^2-9 )

1*x^2 = 9 // : 1

x^2 = 9

x^2 = 9 // ^ 1/2

abs(x) = 3

x = 3 or x = -3

x in { -3} 

x in { 0, 3 }

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